Power vs Type II error (power = 1 - beta)

By Jude Wallis · Published

A Type II error is failing to reject a false null hypothesis, with probability beta. Power is rejecting it correctly, with probability 1 minus beta. They are one fact stated from opposite ends. Neither is a single number for a test: both are computed against one specific true parameter value.

AP Statistics: Unit 3 (topics 3.8 Potential Errors When Performing Tests). Power and the Type II error rate belong to Unit 3 topic 3.8, Potential Errors When Performing Tests, in the Fall 2026 AP Statistics course. The z test used throughout has a known sigma, so every figure on this page can be checked against a z table by hand, up to the rounding of the critical value.

Power vs Type II error: the short answer

Both describe what happens when the null hypothesis H0H_0 is false. A Type II error is failing to reject it anyway, and its probability is β\beta ("beta"). Power is the other outcome, correctly rejecting a false H0H_0, with probability 1β1 - \beta. The two probabilities add to 1 because the two outcomes are the only two available. There is one quantity here, not two.

So the interesting part is not the difference. It is the qualifier both of them carry, and it is the one students drop. Neither β\beta nor power is a property of a test on its own. Each is computed by naming one specific value the parameter might really have, and each changes the instant you name a different one. The same test has one power against μ=105\mu = 105 and a different power against μ=108\mu = 108. A power quoted with no alternative value attached is not a number anyone can check.

Neither one is a single number for a test

Take the z test the site's power visualizer runs, chosen because the population standard deviation is known, so nothing is estimated on the way to the answer and every number below can be checked against a z table.

Test H0:μ=100H_0: \mu = 100 against Ha:μ>100H_a: \mu > 100, with σ\sigma ("sigma") known to be 15 and n=25n = 25. The standard error is 15/25=315/\sqrt{25} = 3, and at α=0.05\alpha = 0.05 the test rejects once the sample mean xˉ\bar{x} ("x-bar") clears 100+1.6449(3)=104.9347100 + 1.6449(3) = 104.9347. That zz^* is the four-decimal critical value; a z table prints it as 1.645, which shifts the cutoff to 104.935 and every probability below by less than 0.0001.

Nothing in that setup mentions the truth. Supply one and the two numbers appear.

If the true μ\mu isPowerChance of failing to reject
1000.05000.9500
1020.16400.8360
1050.50870.4913
1080.84660.1534
1100.95430.0457

The test never changed. The cutoff sat at 104.9347 in every row, α\alpha stayed at 0.05, and nn stayed at 25. Only the assumed truth moved, and power went from the significance level itself to near certainty. Read the last two columns and you have read power and β\beta at the same time, which is the whole relationship.

One caution about the first row. The right-hand column is β\beta in every row except that one, where μ=100\mu = 100 makes H0H_0 true. A Type II error cannot happen when the null is correct, so 0.9500 there is the chance of a correct decision, not an error rate.

The two boundaries that catch people out

Two rows of that table deserve their own note, because both contradict a rule students invent.

Power equals α\alpha when the truth sits at the null value. At μ=100\mu = 100 power reads 0.0500, exactly the significance level. With no effect to detect, the only rejections still available are Type I errors, so the rejection rate is α\alpha by construction. Change nn to 10 or to 200 and that row does not move.

Power can fall below α\alpha. This test looks upward only, so it is blind to a true mean under 100. Against μ=95\mu = 95 its power is 0.0005, roughly a hundredth of α\alpha. The two-sided version of the same test cannot do that: with α\alpha split across both tails the power curve bottoms out at 0.0500 when μ=100\mu = 100 and climbs in both directions, reaching 0.3848 against μ=95\mu = 95. The two-sided test pays for that coverage elsewhere, since against μ=105\mu = 105 its power is 0.3848 rather than 0.5087. That is one concrete price of the one-sided or two-sided decision.

The four levers, and which way each one pushes

Four things move power. Every direction below was recomputed one lever at a time, holding the other three fixed, from the same baseline: the test above aimed at a true mean of 105, where power is 0.5087 and β\beta is 0.4913.

LeverChangePowerBetaWhat it costs
Sample size nn25 to 1000.5087 to 0.95430.4913 to 0.0457More data, and α\alpha stays at 0.0500
Significance level α\alpha0.05 to 0.100.5087 to 0.64990.4913 to 0.3501The Type I error rate doubles
Distance of the truth from the null105 to 1080.5087 to 0.84660.4913 to 0.1534Nothing, and it is not yours to set
Variability σ\sigma15 to 100.5087 to 0.80380.4913 to 0.1962A cleaner measurement process or a design that removes noise, and α\alpha stays at 0.0500

The cost column is where they differ, and it is what a good exam answer names. Two of them buy power outright, and they buy it the same way: raising nn and lowering σ\sigma both shrink the standard error while leaving α\alpha exactly where you set it. Raising α\alpha is a trade, not a gain: it lowers β\beta and raises the false-alarm rate in the same move, which is the judgment covered in how to choose a significance level. The distance from the null is not a lever at all, only a fact you discover afterward. The σ\sigma route is the one students forget on free-response: a tighter measurement process, or a design that strips out a source of variation, raises power with no extra data and no extra false alarms; see standard error vs standard deviation for why those two are not the same quantity.

Say which lever you mean. "Increasing the sample size increases power" is true only with the other three held fixed, and dropping that qualifier is the most common way a correct sentence turns into a wrong one.

Power vs Type II error side by side

FeaturePowerType II error
The outcomeRejecting a false H0H_0, the correct callFailing to reject a false H0H_0, a miss
Probability1β1 - \betaβ\beta
Possible only whenH0H_0 is falseH0H_0 is false
Needs a stated alternative valueYesYes
Chosen by youNoNo
In the baseline test above0.5087 against μ=105\mu = 1050.4913 against μ=105\mu = 105
Relationship to α\alphaEquals α\alpha when the truth is the null valueNone fixed: here 0.05 and 0.4913

Wherever the two columns differ they are describing one event from opposite ends, and the two numeric rows differ by nothing more than a subtraction. The rest of the rows are shared outright, because these are one event counted twice. In practice the choice between the words is just whichever one the question asks you to name.

The mix-ups worth killing

Five sentences to stop writing, each with the correction attached.

  • "Power is 0.5087, so the null is about 51 percent likely to be false." Power says nothing about whether H0H_0 is false. It assumes a stated alternative value is already the truth and reports how often the test would notice.
  • "Alpha and beta add to 1." They do not. In the baseline test they are 0.05 and 0.4913, which sum to 0.5413 and mean nothing. Power and β\beta are the complements; α\alpha and β\beta are unrelated numbers about two different states of the world.
  • "My p-value was 0.31, so there is a 31 percent chance I made a Type II error." A p-value is computed assuming H0H_0 is true, and under a true H0H_0 a Type II error cannot occur at all. β\beta is never read off your data; see what a p-value means.
  • "This test has a power of 0.80." Against what? Without the alternative value the sentence carries no information, and the table above is why: the same test ran from 0.0500 to 0.9543 with nothing changed but the assumed truth.
  • "We failed to reject, so there is no effect." A failure to reject means the evidence was not convincing, not that H0H_0 is true. A low-power test fails to reject constantly even when an effect is real, which is exactly why "no convincing evidence" and "no effect" are different claims. The full reasoning is in Type I vs Type II error and power.

Power and beta against one stated alternative

A z test uses H0:μ=100H_0: \mu = 100 against Ha:μ>100H_a: \mu > 100 at α=0.05\alpha = 0.05, with σ=15\sigma = 15 known and n=25n = 25. Find the power and the probability of a Type II error when the true mean is 107.

  1. Standard error first: σ/n=15/25=15/5=3\sigma/\sqrt{n} = 15/\sqrt{25} = 15/5 = 3.

  2. Put the rejection rule on the sample-mean scale. The upper critical value for α=0.05\alpha = 0.05 is z=1.6449z^* = 1.6449, the four-decimal version of the 1.645 a z table prints, so the test rejects when xˉ>100+1.6449(3)=104.9347\bar{x} > 100 + 1.6449(3) = 104.9347.

  3. Now switch distributions. If the truth is μ=107\mu = 107, sample means center at 107 with the same standard error of 3.

  4. Standardize the cutoff against that true distribution: z=(104.9347107)/3=0.6884z = (104.9347 - 107)/3 = -0.6884.

  5. Power is the chance of landing in the rejection region under the truth: P(Z>0.6884)=0.7544P(Z > -0.6884) = 0.7544.

  6. The Type II error is the complement: β=10.7544=0.2456\beta = 1 - 0.7544 = 0.2456.

  7. Check the identity: 0.7544+0.2456=1.00000.7544 + 0.2456 = 1.0000, which is what power=1β\text{power} = 1 - \beta requires.

Power is 0.7544 and β=0.2456\beta = 0.2456, both against μ=107\mu = 107 and against nothing else. Notice that step 2 used no information about the truth and step 4 used nothing else: the cutoff belongs to the test, the two probabilities belong to the test plus one named alternative.

One test, two powers

Keep that test exactly as it was: H0:μ=100H_0: \mu = 100 against Ha:μ>100H_a: \mu > 100, α=0.05\alpha = 0.05, σ=15\sigma = 15, n=25n = 25, rejecting when xˉ>104.9347\bar{x} > 104.9347. A student writes "the power of this test is". Compute the power against μ=103\mu = 103 and against μ=108\mu = 108, then say what is wrong with the phrase.

  1. The cutoff is built from H0H_0, α\alpha, σ\sigma, and nn only, so it stays at 104.9347 for both, and the standard error stays at 3.

  2. Against μ=103\mu = 103: z=(104.9347103)/3=0.6449z = (104.9347 - 103)/3 = 0.6449, so power is P(Z>0.6449)=0.2595P(Z > 0.6449) = 0.2595 and β=10.2595=0.7405\beta = 1 - 0.2595 = 0.7405.

  3. Against μ=108\mu = 108: z=(104.9347108)/3=1.0218z = (104.9347 - 108)/3 = -1.0218, so power is P(Z>1.0218)=0.8466P(Z > -1.0218) = 0.8466 and β=10.8466=0.1534\beta = 1 - 0.8466 = 0.1534.

  4. Compare the inputs. Nothing about α\alpha, nn, σ\sigma, the hypotheses, or the cutoff differs between the two calculations.

  5. The only thing that changed is the alternative value the power was aimed at, and the answer moved from 0.2595 to 0.8466.

0.2595 against μ=103\mu = 103 and 0.8466 against μ=108\mu = 108. There is no single power of this test, so the phrase is incomplete rather than wrong: a power or a β\beta becomes a real number only once the alternative value it targets is named. That is also why β\beta can never be recovered from your sample, which knows nothing about which alternative you had in mind.

Frequently asked questions

Is power just 1 minus the Type II error rate?

Yes. Power is the probability of correctly rejecting a false null hypothesis and beta is the probability of failing to reject it, so the two always add to 1. The catch is that both are computed against one specific true parameter value, so a power and a beta only pair up when they name the same alternative.

Do alpha and beta add to 1?

No, and they have no fixed relationship at all. In the z test on this page alpha is 0.05 and beta against a true mean of 105 is 0.4913, which sum to 0.5413. Alpha is the error rate when the null is true; beta is the error rate when it is false. Power and beta are the complements, not alpha and beta.

Can power ever be smaller than alpha?

Yes, for a one-sided test aimed the wrong way. The upper-tailed test here has power 0.0005 against a true mean of 95, far below its alpha of 0.05, because it cannot detect an effect in the direction it is not looking. A two-sided test cannot fall below alpha: its power curve bottoms out at alpha when the truth equals the null value.

Can I work out beta from my p-value?

No. A p-value is computed assuming the null hypothesis is true, and a Type II error is only possible when the null is false, so the p-value carries no information about beta. Beta is a property of the test aimed at an alternative value you never get to observe, not something the data report.

How do I raise power without raising the Type I error rate?

Increase the sample size, or reduce variability through a cleaner measurement process or a better design. In the test on this page, moving n from 25 to 100 takes power against a true mean of 105 from 0.5087 to 0.9543 while alpha stays at 0.0500. Raising alpha also raises power, but it buys that by making false alarms more common.