AP Statistics cram sheet: every formula and template

By Jude Wallis · Published

This cram sheet condenses AP Statistics by unit: the formula-sheet must-knows, the interpretation templates for confidence intervals, p-values, slope, and r-squared, the condition checklists, the State-Plan-Do-Conclude frame, and the exam format.

A whole-course review for the Fall 2026 AP Statistics exam (first administered May 2027): three-hour digital exam, 42 multiple-choice questions and 4 free-response questions weighted 50/50, formula sheet and tables provided. Chi-square goodness-of-fit, the geometric distribution, and inference for a regression slope are not on this exam.

How the exam is scored

The AP Statistics exam is 3 hours long and taken fully digitally in Bluebook. Section I is 42 multiple-choice questions in 90 minutes and counts for 50% of your score. Section II is 4 free-response questions worth 10 points each in 90 minutes, the other 50%, so each free-response question is 12.5% of the exam.

The free-response questions come in a fixed order:

  • Question 1 uses Practices 1 and 2 (formulating questions and collecting data).
  • Question 2 uses Practices 3 and 4 (analyzing data and interpreting results).
  • Question 3 is inference: either a hypothesis test or a confidence interval.
  • Question 4 uses Practices 2, 3, and 4.

A graphing calculator with statistical capabilities is expected, and a formula sheet and tables are provided in both sections; the sheet is laid out at formulas. The multiple-choice weighting by unit is roughly Unit 1 at 20-30%, Unit 2 at 15-25%, Unit 3 at 15-25%, Unit 4 at 10-20%, and Unit 5 at 10-20%. For the full framework, see AP Statistics.

Unit 1: exploring one-variable data and collecting data

Two formulas anchor this unit: the sample mean xˉ=xin\bar{x} = \frac{\sum x_i}{n} (add the values, divide by the sample size nn) and the sample standard deviation s=(xixˉ)2n1s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}, which divides by n1n-1 because it comes from a sample, not the whole population.

Describe any distribution by shape, center, spread, and unusual features (outliers), always in context. The 1.5×IQR1.5 \times \text{IQR} rule flags a value as an outlier if it falls below Q11.5(IQR)Q_1 - 1.5(\text{IQR}) or above Q3+1.5(IQR)Q_3 + 1.5(\text{IQR}), where the interquartile range is IQR=Q3Q1\text{IQR} = Q_3 - Q_1. For roughly normal data, the empirical rule puts about 68% of values within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3.

Collecting data is the other half of this unit. Know simple random, stratified, and cluster sampling, and the bias traps of undercoverage, nonresponse, and voluntary response. An experiment needs comparison, random assignment, and replication, and only a randomized experiment supports a cause-and-effect claim.

More detail: standard deviation by hand, the 1.5 IQR rule, the empirical rule, experiments vs observational studies, and Unit 1.

Unit 2: probability, random variables, and distributions

Probability rules to have cold:

  • General addition: P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B), where ABA \cup B means "A or B".
  • Conditional: P(AB)=P(AB)P(B)P(A|B) = \frac{P(A \cap B)}{P(B)}, where ABA \cap B means "A and B".
  • Independent events: P(AB)=P(A)P(B)P(A \cap B) = P(A)P(B). Mutually exclusive (disjoint) events instead have P(AB)=0P(A \cap B) = 0, which is not the same as independent.

For a discrete random variable XX, the mean (expected value) is μX=xiP(xi)\mu_X = \sum x_i \cdot P(x_i) and the standard deviation is σX=(xiμX)2P(xi)\sigma_X = \sqrt{\sum (x_i - \mu_X)^2 \cdot P(x_i)}. A binomial variable (a fixed number of independent trials with the same success probability pp) has P(X=x)=(nx)px(1p)nxP(X=x) = \binom{n}{x} p^x (1-p)^{n-x}, mean μX=np\mu_X = np, and standard deviation σX=np(1p)\sigma_X = \sqrt{np(1-p)}.

For a normal model, standardize with the z-score z=xμσz = \frac{x - \mu}{\sigma} (how many standard deviations xx sits from the mean μ\mu) and read the area from the z-table. The sampling distribution of xˉ\bar{x} has mean μ\mu and standard deviation σ/n\sigma/\sqrt{n}; the central limit theorem makes it approximately normal for a large sample (about n30n \ge 30), even when the population is not.

More detail: disjoint vs independent events, binomial probability, the central limit theorem, and Unit 2.

Unit 3: inference for proportions

One proportion. The standard error of the sample proportion p^\hat{p} (read "p-hat") is SEp^=p^(1p^)nSE_{\hat{p}} = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} for a confidence interval. A significance test instead uses the null value p0p_0 inside the root, p0(1p0)n\sqrt{\frac{p_0(1-p_0)}{n}}, with z=p^p0SEz = \frac{\hat{p} - p_0}{SE}.

Two proportions. The interval standard error is p^1(1p^1)n1+p^2(1p^2)n2\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}. A test pools the two samples first: p^c=n1p^1+n2p^2n1+n2\hat{p}_c = \frac{n_1\hat{p}_1 + n_2\hat{p}_2}{n_1 + n_2}, then uses p^c\hat{p}_c in the standard error.

Chi-square (two-way tables). The statistic is χ2=(OE)2E\chi^2 = \sum \frac{(O-E)^2}{E}, where OO is an observed count and EE is the expected count row total×column totalgrand total\frac{\text{row total} \times \text{column total}}{\text{grand total}}. A test of homogeneity compares one categorical variable across several groups; a test of independence checks whether two variables are associated within one sample.

Common critical values from the z-table: 90% uses z=1.645z^* = 1.645, 95% uses 1.961.96, and 99% uses 2.5762.576. More detail: one-proportion vs two-proportion z test, chi-square tests explained, the proportion z-test calculator, and Unit 3.

Unit 4: inference for means

Every mean procedure uses tt, not zz, because you estimate the population standard deviation with the sample standard deviation ss. For the one-sample and paired procedures the degrees of freedom are n1n-1; for two independent samples the degrees of freedom come from your calculator, or, conservatively, the smaller of n11n_1 - 1 and n21n_2 - 1.

  • One sample: SExˉ=snSE_{\bar{x}} = \frac{s}{\sqrt{n}} and t=xˉμ0SEt = \frac{\bar{x} - \mu_0}{SE}, where μ0\mu_0 is the claimed mean.
  • Two independent samples: SE=s12n1+s22n2SE = \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}.
  • Paired data: compute each difference first, then run a one-sample tt on the differences.

If the population standard deviation σ\sigma is somehow known (rare in practice), the sampling distribution standard deviation is σxˉ=σn\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}. Read the critical value tt^* from the t-table using your degrees of freedom.

More detail: t-test vs z-test, how to calculate a confidence interval, the one-sample t-test calculator, and Unit 4.

Unit 5: regression analysis

The least-squares regression line predicts y^=a+bx\hat{y} = a + bx, where aa is the y-intercept and bb is the slope. The correlation rr runs from 1-1 to 11 and measures the direction and strength of a linear association, while r2r^2 is the fraction of the variation in yy that the linear model with xx explains.

A residual is observedpredicted\text{observed} - \text{predicted}, that is yy^y - \hat{y}. A residual plot with no leftover pattern supports using a straight-line model; a clear curve does not. On the Fall 2026 exam, regression is descriptive only, so you interpret the slope, rr, r2r^2, and residuals but you do not run a significance test for the slope.

The slope and r2r^2 interpretation templates are in the section below. More detail: least-squares regression line, r vs r-squared, how to interpret residual plots, the regression calculator, and Unit 5.

The inference frame: State, Plan, Do, Conclude

Every inference free-response answer, and many multiple-choice setups, follows four steps.

  1. State: name the parameter in words, then write both hypotheses about that parameter, not about the sample. Use pp for a population proportion or μ\mu for a population mean.
  2. Plan: name the exact procedure and check its conditions with numbers.
  3. Do: show the sample statistic, the test statistic or interval, and the p-value.
  4. Conclude: compare the p-value to the significance level α\alpha and answer in context, or interpret the interval in context.

Two formula-sheet identities drive the Do step: the standardized test statistic is statisticparameterstandard error\frac{\text{statistic} - \text{parameter}}{\text{standard error}}, and a confidence interval is statistic±(critical value)(standard error)\text{statistic} \pm (\text{critical value})(\text{standard error}). For point-by-point scoring, see the FRQ guide; to pick the right procedure, see which statistical test to use.

Condition checklists

Almost every inference procedure checks the same families of conditions. Show the numbers, not just the names, or you lose the condition point.

  • Random: the data comes from a random sample or a randomized experiment.
  • 10%: when sampling without replacement, the sample is at most 10% of the population, so the trials stay roughly independent.
  • Large counts (proportions): npnp and n(1p)n(1-p) are each at least 10. Use p0p_0 for a test and p^\hat{p} for an interval.
  • Normal or large sample (means): the population is stated to be normal, or the sample size is at least 30 so the central limit theorem applies, or a graph of the sample shows no strong skew and no outliers. This is the condition the tt procedures need.

Interpretation templates worth memorizing

Scorers want the result tied back to the context. Fill the brackets with the problem's own words and units.

  • Confidence interval: "We are C%C\% confident that the interval from [low] to [high] captures the true [parameter in context]." The confidence level describes the method, not one interval. See what 95% confidence means.
  • P-value: "Assuming H0H_0 is true, the p-value is the probability of getting a statistic at least as extreme as the one observed." If the p-value is at most α\alpha, reject H0H_0 and state convincing evidence for HaH_a in context; otherwise fail to reject. See what a p-value means.
  • Slope: "For each additional one [x-unit], the predicted [y] changes by bb [y-units]."
  • r-squared: "About [r2r^2]% of the variation in [y] is explained by the linear model with [x]."

Classic point-losers

These are the mistakes that cost the most points, and every one is avoidable:

  • Dividing by nn instead of n1n-1 for a sample standard deviation, or mixing up the sample and population formulas.
  • Writing hypotheses about a sample statistic like p^\hat{p} or xˉ\bar{x} instead of the parameter pp or μ\mu.
  • Naming a condition without showing the numbers that make it hold.
  • A conclusion with no context, a sentence that could be pasted onto any problem.
  • Writing "accept H0H_0"; you fail to reject it, you never accept it.
  • Treating mutually exclusive events as independent, or claiming causation from an observational study.
  • Confusing rr with r2r^2, or reporting a bare calculator command with no values shown.

A 95% confidence interval for a mean, with the interpretation template

A random sample of 5 tomato plants has heights, in centimeters, of 8, 10, 12, 14, and 16. Assume the heights are roughly symmetric with no outliers. Build a 95% confidence interval for the true mean height of all such plants, and interpret it.

  1. Sample mean: xˉ=8+10+12+14+165=605=12\bar{x} = \frac{8 + 10 + 12 + 14 + 16}{5} = \frac{60}{5} = 12 cm, where xˉ\bar{x} is the sample mean.

  2. Deviations from 12 are 4,2,0,2,4-4, -2, 0, 2, 4; their squares are 16,4,0,4,1616, 4, 0, 4, 16, which sum to 40.

  3. Sample standard deviation: s=4051=404=10=3.1623s = \sqrt{\frac{40}{5-1}} = \sqrt{\frac{40}{4}} = \sqrt{10} = 3.1623 cm.

  4. Standard error: SExˉ=sn=3.16235=3.16232.2361=1.4142SE_{\bar{x}} = \frac{s}{\sqrt{n}} = \frac{3.1623}{\sqrt{5}} = \frac{3.1623}{2.2361} = 1.4142.

  5. Critical value: with n1=4n - 1 = 4 degrees of freedom, the 95% value from the t-table is t=2.776t^* = 2.776.

  6. Margin of error: t×SE=2.776×1.4142=3.926t^* \times SE = 2.776 \times 1.4142 = 3.926.

  7. Interval: 12±3.92612 \pm 3.926, which is (8.074,15.926)(8.074, 15.926) cm.

  8. Interpret: we are 95% confident that the interval from 8.074 to 15.926 cm captures the true mean height of all such tomato plants.

The 95% confidence interval is 12±3.92612 \pm 3.926, or about (8.07,15.93)(8.07, 15.93) cm. We are 95% confident this interval captures the true mean height of all such plants.

Mean and standard deviation of a discrete random variable

A random variable XX takes the values 0, 1, 2, and 3 with probabilities 0.1, 0.2, 0.4, and 0.3. Find its mean (expected value) and its standard deviation.

  1. Check the probabilities sum to 1: 0.1+0.2+0.4+0.3=1.00.1 + 0.2 + 0.4 + 0.3 = 1.0.

  2. Mean: μX=xiP(xi)=0(0.1)+1(0.2)+2(0.4)+3(0.3)=0+0.2+0.8+0.9=1.9\mu_X = \sum x_i \cdot P(x_i) = 0(0.1) + 1(0.2) + 2(0.4) + 3(0.3) = 0 + 0.2 + 0.8 + 0.9 = 1.9.

  3. Deviations from 1.9 are 1.9,0.9,0.1,1.1-1.9, -0.9, 0.1, 1.1; their squares are 3.61,0.81,0.01,1.213.61, 0.81, 0.01, 1.21.

  4. Weight each square by its probability: 3.61(0.1)+0.81(0.2)+0.01(0.4)+1.21(0.3)=0.361+0.162+0.004+0.363=0.8903.61(0.1) + 0.81(0.2) + 0.01(0.4) + 1.21(0.3) = 0.361 + 0.162 + 0.004 + 0.363 = 0.890. This sum is the variance.

  5. Standard deviation: σX=0.890=0.9434\sigma_X = \sqrt{0.890} = 0.9434.

The mean is μX=1.9\mu_X = 1.9 and the standard deviation is σX=0.8900.943\sigma_X = \sqrt{0.890} \approx 0.943.

Frequently asked questions

What formulas do I need to memorize for AP Statistics?

Fewer than you might think, because a formula sheet is provided in both sections and is laid out at formulas. What you actually have to know is which formula to use, how to read its symbols, and the conditions and interpretation templates the sheet does not give you. Spend cram time on choosing procedures and writing conclusions in context, not on rote memorization.

How is the AP Statistics exam scored?

The two sections are weighted equally. Section I is 42 multiple-choice questions worth 50%, and Section II is 4 free-response questions worth 10 points each and 50%, so each free-response question is 12.5% of your score. Free-response answers are graded component by component, so labeling each step helps a scorer find every point.

What is the fastest way to lose points on the free response?

Leaving out the context. A decision or an interval with no sentence tied to the problem's setting loses the interpretation point, even when the arithmetic is right. The next most common losses are naming conditions without showing the numbers and writing "accept the null" instead of "fail to reject".