Empirical rule (68-95-99.7) and normal distribution

By Jude Wallis · Published

About 68% of values in an approximately normal distribution fall within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3. This 68-95-99.7 empirical rule only applies when the data is roughly bell-shaped and symmetric.

AP Statistics: Unit 2 (topics 2.11 The Normal Distribution). In the Fall 2026 AP Statistics course, the normal distribution and the empirical rule are Unit 2, topic 2.11 (Probability, Random Variables, and Probability Distributions).

What the empirical rule says

The empirical rule, also called the 68-95-99.7 rule, describes how values spread out in a normal distribution. For data that is approximately normal:

  • About 68% of values fall within 1 standard deviation of the mean.
  • About 95% of values fall within 2 standard deviations of the mean.
  • About 99.7% of values fall within 3 standard deviations of the mean.

The mean is written μ\mu (the center of the distribution) and the standard deviation is written σ\sigma (a measure of how spread out the values are). So the three intervals are μ±σ\mu \pm \sigma, μ±2σ\mu \pm 2\sigma, and μ±3σ\mu \pm 3\sigma.

The word 'about' matters. These are rounded from the exact normal-curve percentages of 68.27%, 95.45%, and 99.73%, and real data only approximates them.

The normal distribution and its bell shape

A normal distribution is a symmetric, bell-shaped curve. Picture a smooth mound that is highest at the center and tails off evenly on both sides. The peak sits at the mean μ\mu, and the left half is a mirror image of the right half. The College Board describes the normal curve as continuous, unimodal, bell-shaped, and symmetric.

Because the curve is symmetric, half of the values (50%) sit below the mean and half sit above it. Standard deviations mark off equal steps as you move away from the center. If you stand at the mean and walk out one σ\sigma in each direction, you capture the middle 68% of the area under the curve. Walk out to 2σ2\sigma and you capture 95%; walk out to 3σ3\sigma and you capture 99.7%.

The size of σ\sigma controls the width, not the shape. A small standard deviation makes the curve tall and narrow with values clustered near the mean, while a large standard deviation makes it short and wide. Either way the 68-95-99.7 percentages stay the same, because they are measured in standard deviations rather than in raw units.

Almost all of a normal distribution (99.7%) sits within 3 standard deviations of the mean, so the tails beyond that point are very thin.

How to sketch the curve and label it

Drawing the curve makes empirical-rule problems much easier. Here is the sketch in words.

Start with a horizontal axis. Put a tall tick in the middle and label it with the mean μ\mu. Draw six evenly spaced ticks around it, three on each side, and label them μ3σ\mu - 3\sigma, μ2σ\mu - 2\sigma, μσ\mu - \sigma, then μ+σ\mu + \sigma, μ+2σ\mu + 2\sigma, μ+3σ\mu + 3\sigma. For a distribution with μ=150\mu = 150 and σ=20\sigma = 20, those ticks read 90, 110, 130, 150, 170, 190, 210.

Now draw a smooth bell over the axis: highest above the mean, dropping symmetrically, and nearly touching the axis by the 3σ3\sigma ticks. Write 34% in each band next to the mean, 13.5% in each band between 1 SD and 2 SD, and 2.35% in each band between 2 SD and 3 SD. To find the area for any question, shade the matching region and add the labeled percentages.

The normal distribution percentages in each region

You can split the rule into smaller pieces. Each standard-deviation band holds a known share of the area:

  • From the mean out to 1 SD, on one side: 34% (half of 68%).
  • Between 1 SD and 2 SD, on one side: 13.5%.
  • Between 2 SD and 3 SD, on one side: 2.35%.
  • Beyond 3 SD, on one side: 0.15%.

These come from the symmetry of the curve. For example, 95% lies within 2 SD and 68% lies within 1 SD, so the two bands between 1 SD and 2 SD together hold 95%68%=27%95\% - 68\% = 27\%, which is 13.5% on each side.

This breakdown answers 'what percent is above' or 'what percent is below' a whole-SD cutoff. The percent above the point 1 SD above the mean is 13.5%+2.35%+0.15%=16%13.5\% + 2.35\% + 0.15\% = 16\%, which also equals (100%68%)/2(100\% - 68\%) / 2.

When not to use the empirical rule

The empirical rule only works when the distribution is approximately normal, meaning roughly symmetric and single-peaked. If the data is skewed or has strong outliers, the 68-95-99.7 percentages do not apply.

Skewed data is the most common trap. Incomes and house prices often have a long right tail, so the interval μ±σ\mu \pm \sigma can stretch past values that are impossible, and the true percentage within 1 SD will not be 68%. Applying the rule to skewed data gives wrong answers.

Before using the rule, check the shape. A dotplot, histogram, or boxplot that looks roughly symmetric and single-peaked is a good sign. If you see two peaks, a long tail, or extreme outliers, use the actual distribution instead of the rule.

For values that are not a whole number of SDs, use z-scores

The empirical rule gives clean answers only at 1, 2, and 3 standard deviations. For any other cutoff you need a z-score, which counts how many standard deviations a value xx sits from the mean:

z=xμσz = \frac{x - \mu}{\sigma}

A z-score of 0.75 means a value sits 0.75 standard deviations above the mean, which the empirical rule cannot handle directly. Once you have the z-score, a z-table or the normal distribution calculator gives the area, and that area is the percentage of values below your cutoff.

See how to find a z-score for the full method. The second worked example below shows the empirical rule and the z-score approach side by side.

Where this fits in AP Statistics

The normal distribution is Unit 2, topic 2.11 in the Fall 2026 AP Statistics course (Probability, Random Variables, and Probability Distributions). You use the 68-95-99.7 rule for quick estimates at whole standard deviations and z-scores with the provided table for precise probabilities.

On the exam, a graphing calculator with statistical capabilities is expected, and formulas and tables are provided for both sections. For the official course framework, see AP Central.

Reading percentages straight from the empirical rule

Apple weights from an orchard are approximately normal with mean μ=150\mu = 150 grams and standard deviation σ=20\sigma = 20 grams. (a) What percent of apples weigh between 130 and 170 grams? (b) What percent weigh more than 190 grams? (c) What percent weigh between 110 and 170 grams?

  1. Mark the standard-deviation cutoffs by starting at μ=150\mu = 150 and stepping by σ=20\sigma = 20. One SD gives 15020=130150 - 20 = 130 and 150+20=170150 + 20 = 170. Two SD gives 15040=110150 - 40 = 110 and 150+40=190150 + 40 = 190. Three SD gives 15060=90150 - 60 = 90 and 150+60=210150 + 60 = 210.

  2. (a) The interval 130 to 170 is exactly μ±σ\mu \pm \sigma, which is 1 SD on each side. The empirical rule gives about 68%.

  3. (b) 190 grams is 150+2(20)150 + 2(20), so it is 2 SD above the mean. The percent above 2 SD is (100%95%)/2=2.5%(100\% - 95\%) / 2 = 2.5\%.

  4. (c) 110 grams is 2 SD below the mean and 170 grams is 1 SD above. Split at the mean: from the mean down to 2 SD below holds 95%/2=47.5%95\% / 2 = 47.5\%, and from the mean up to 1 SD above holds 68%/2=34%68\% / 2 = 34\%. Add them: 47.5%+34%=81.5%47.5\% + 34\% = 81.5\%.

(a) about 68%; (b) about 2.5%; (c) about 81.5%.

When the cutoff is not a whole standard deviation

Using the same apples (approximately normal, mean μ=150\mu = 150 grams, standard deviation σ=20\sigma = 20 grams), what percent of apples weigh less than 165 grams?

  1. Check whether 165 is a whole number of standard deviations above the mean: 165150=15165 - 150 = 15 grams, and 15/20=0.7515 / 20 = 0.75 of a standard deviation. Because 0.75 is not a whole number, the empirical rule cannot answer this directly.

  2. Compute the z-score, which counts standard deviations from the mean: z=xμσ=16515020=1520=0.75z = \frac{x - \mu}{\sigma} = \frac{165 - 150}{20} = \frac{15}{20} = 0.75.

  3. Look up z=0.75z = 0.75 in a z-table (or use the normal distribution calculator). The area to the left of 0.75 is 0.7734.

  4. Convert the area to a percent: 0.7734=77.34%0.7734 = 77.34\%. This is a sensible answer because 165 grams is between the mean (50% below it) and 1 SD above the mean (84% below it).

About 77.34% of apples weigh less than 165 grams. The empirical rule alone could only place the answer between 50% and 84%, so the z-score gives the precise figure.

Frequently asked questions

Is the empirical rule the same as the 68-95-99.7 rule?

Yes, they are two names for the same rule. Both refer to the fact that about 68% of an approximately normal distribution lies within 1 standard deviation of the mean, about 95% within 2, and about 99.7% within 3.

Why is it called the empirical rule?

The name reflects that the percentages summarize a pattern seen in real, approximately normal data. The exact figures come from the mathematics of the normal curve, and 'empirical' points to how closely they match observed bell-shaped distributions.

What percent of data is between 1 and 2 standard deviations from the mean?

About 27% total, split as 13.5% on each side. You get this from 95%68%=27%95\% - 68\% = 27\%, because 95% lies within 2 SD and 68% lies within 1 SD, and the symmetry of the curve divides the leftover evenly.

Can I use the empirical rule for any data set?

No. It only applies when the distribution is approximately normal, meaning roughly symmetric and single-peaked. For skewed or bimodal data, use z-scores and the actual distribution rather than the 68-95-99.7 percentages.